how electronic gates work

by:Getian     2020-08-08
Play with Boolean doors if you order parts with a form from the previous page, you should have six different chips with six different types of doors: Let\'s start with 7408 and chips.
If you look at the chip, there will usually be a point at pin 1, or an indent at the end of pin 1 of the chip, or some other mark to indicate pin 1.
Push the chip into the breadboard to cross the center channel.
As can be seen from the figure, on all chips, pin 7 must be connected to ground and pin 14 must be connected to 5 volts.
So connect these two pins properly. (
If you connect back, you burn the chip out, so don\'t connect back.
If you accidentally burn the chip out, throw it away so you don\'t confuse it with your good parts. )
Now, connect an LED and resistor between the pin 3 of the chip and the ground.
The LED should be lit.
If not, please reverse the LED to light up.
Your IC should be like this: this is what is happening.
In TTL, 5 represents the binary \"1\" and the binary \"0 \".
\"If the input pin of the gate is not connected to anything, it will\" float high \", which means that the gate assumes a 1 on the pin.
Therefore, and the gate should see 1s on the and B inputs, which means that the output of pin 3 provides A 5 V voltage.
So LED lights.
If ground pin 1 or 2 or both on the chip, the LED will go out.
This is the standard behavior of AND gate as described in How the Boolean logic works.
Try by connecting other doors on the breadboard to see if they all run according to the logic table in the Boolean logic article.
Then try to connect something more complex.
For example, connect the Q bits of a foreign or gate or full-joiner to see if their behavior is as expected.
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